东大20秋学期《测试技术基础》在线平时作业1参考-东北大学-无忧答案网

在线作业 发表于 2020-9-9 21:29:49

东大20秋学期《测试技术基础》在线平时作业1参考

20秋学期《测试技术基础》在线平时作业1
1.[单选题] <span style="FONT-FAMILY: 宋体; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">两个信号叠加:<span style="FONT-FAMILY: 宋体; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><img width="597" height="143" alt="" src="http://file.open.com.cn/ItemDB/65628/890c97bd-5f0a-4320-809c-f8ca9e0bde7d/2014610214012968.jpg" />
附件是答案，核对题目下载
A.A
B.B
C.C
D.D
答:——C——
2.[单选题] 按照奈奎斯特采样定理，采样频率至少为（）（A）有用的最高频率的一半(B)有用的最高频率的两倍(C)与有用的最高频率相同(D)有用的最高频率的3倍
A.A
B.B
C.C
D.D
答:——B——
3.[单选题] 两个信号叠加:<img width="595" height="159" alt="" src="http://file.open.com.cn/ItemDB/65628/6ac95ca9-0f80-46d5-8105-b2e8015e180d/2014610181138149.jpg" />
A.A
B.B
C.C
D.D
答:——C——
4.[单选题] <span style="FONT-SIZE: 14pt; COLOR: red; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">选择题<span style="FONT-SIZE: 14pt; COLOR: red; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><img height="91" alt="" width="577" src="http://file.open.com.cn/ItemDB/65628/0352e875-55ff-4399-b09b-045ba0d8ee0d/2010131211226348.jpg" />
A.A
B.B
C.C
D.D
答:————
5.[单选题] 在随机误差分析中，标准差<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s决定了随机误差正态分布的形态，<o:p></o:p>下面对<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s1、<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s2和<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s3间的关系表达正确的是（ ）<o:p></o:p>（A）<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s1<<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s2<<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s3 (B) <span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s1><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s2><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s3<o:p></o:p>（C）<span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s2><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s1><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s3 (D) <span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s3><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s1><span style="FONT-FAMILY: Symbol; FONT-SIZE: 12pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-bidi-font-weight: bold; mso-char-type: symbol; mso-symbol-font-family: Symbol" lang="EN-US">s2<img alt="" width="310" height="186" src="http://file.open.com.cn/ItemDB/65628/42fad58e-4f3b-44f2-b788-8877a267fe5a/2014612174516862.jpg" /><o:p></o:p>
A.A
B.B
C.C
D.D
答:————
6.[单选题] <span style="FONT-FAMILY: 宋体; FONT-SIZE: 12pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-bidi-font-family: 'Times New Roman'; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">将若矩形窗函数<span style="FONT-FAMILY: 宋体; FONT-SIZE: 12pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-bidi-font-family: 'Times New Roman'; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA"><img width="499" height="99" alt="" src="http://file.open.com.cn/ItemDB/65628/0556414e-8047-486b-a9ff-d6e0c7a6fcb1/2014615133113244.jpg" />
A.A
B.B
C.C
D.D
答:————
7.[单选题] <span style="FONT-SIZE: 12pt; FONT-FAMILY: 宋体; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-hansi-font-family: 'Times New Roman'; mso-ascii-font-family: 'Times New Roman'; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">带通滤波器<img height="243" width="534" alt="" src="http://file.open.com.cn/ItemDB/65628/e96b64ec-e42f-44aa-9f9a-66b0b4112724/201021165834271.jpg" />
A.A
B.B
C.C
D.D
答:————
8.[单选题] <span style="FONT-SIZE: 14pt; COLOR: red; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA">选择题<img height="143" alt="" width="577" src="http://file.open.com.cn/ItemDB/65628/015bb9f8-e351-4fdd-a9a2-7cf618341889/20101312115316.jpg" />
A.A
B.B
C.C
D.D
答:————
9.[单选题] 选择题1. 概率密度函数曲线下的面积等于（）A. 0.1B. 0.7C. 1.0D. 2.0
A.A
B.B
C.C
D.D
答:————
10.[单选题] 选择题<img alt="" src="http://file.open.com.cn/ItemDB/65628/ba0adc0f-817a-4517-8541-dfd091c915f9/20101312148920.jpg" /> 
A.A
B.B
C.C
D.D
答:————
11.[判断题] 周期信号是能量信号。
A.错误
B.正确
答:————
12.[判断题] 判断题乐器频谱图为离散线谱
A.错误
B.正确
答:————
13.[判断题] 振动的幅值、频率和相位是振动的三个基本参数，称为振动三要素。只要测定这三个要素，也就决定了整个振动运动。（ ）
A.错误
B.正确
答:————
14.[判断题] 线性装置的灵敏度S为常数。（ ）
A.错误
B.正确
答:————
15.[判断题] 判断题热电偶产生的热电势是由两种导体的接触电势和单一导体的温差电势所形成。
A.错误
B.正确东财答案请进 ap5u.com
答:————
16.[判断题] 磁电式速度传感器为惯性式速度传感器，电动势的输出与线圈的运动速度成正比。（ ）
A.错误
B.正确
答:————
17.[判断题] 直接比较型A/D转换器将输入模拟电压信号直接与作为标准的参考电压信号相比较，得到相应的数字编码（）
A.错误
B.正确
答:————
18.[判断题] 当采样频率为信号最高频率的1.5倍时，不会产生频率混叠。（）
A.错误
B.正确
答:————
19.[判断题] 周期信号的三角函数展开形式的频谱是双边谱；复指数展开形式的频谱是单边谱。
A.错误
B.正确
答:————
20.[判断题] 一般非周期信号的频谱具有连续性和衰减性等特性。
A.错误
B.正确
答:————

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东大20秋学期《测试技术基础》在线平时作业1参考